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Erdős–Szekeres convex-polygon problem

Open

erdos-szekeres-convex-polygon

Statement

Let ES(n)\mathrm{ES}(n)ES(n) be the least NNN such that any NNN points in general position contain a convex nnn-gon. Prove the conjectured exact value ES(n)=2 n−2+1\mathrm{ES}(n) = 2^{\,n-2} + 1ES(n)=2n−2+1.

Current frontier

erdosproblems.com/107, OPEN. Erdős–Szekeres proved the upper bound (1935) and the lower bound 2n−2+1≤ES(n)2^{n-2}+1 \leq \mathrm{ES}(n)2n−2+1≤ES(n) (1960), conjecturing equality; Suk (2017), refined by Holmsen–Mojarrad–Pach–Tardos (2020) to 2n+O(nlog⁡n)2^{n+O(\sqrt{n\log n})}2n+O(nlogn​), nearly matches. Exact values are known only through n=6n = 6n=6 (ES(6)=17\mathrm{ES}(6) = 17ES(6)=17).

When this counts as solved

VALUE-DETERMINATION. PROOF_COMPLETE for ES(n)=2n−2+1\mathrm{ES}(n) = 2^{n-2}+1ES(n)=2n−2+1 for all nnn, COUNTEREXAMPLE for a violating nnn. BREAKTHROUGH for a new exact value ES(n)\mathrm{ES}(n)ES(n), n≥7n \geq 7n≥7, or the formula on an infinite subfamily.

Classification

value-determination

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